Lets write the decimal integer n in binary notation and create all its left cycle shifts where first digit of the number goes to the end.
For example, if n = 11, than it will be 1011 in binary notation, cycle shifts are 0111, 1110, 1101, 1011. So the maximal value m among all received numbers equals to 1110[2]
= 14[10]
.
For the number n find the maximal value of m.
One number n (1 ≤ n ≤ 2 ·10^9
).
One number m.