# Fast Exponentiation

Very often arises the problem of effective calculation `x^n`

by given x and n, where n is a positive integer.

For example, assume that it is necessary to calculate the `x^16`

. You can simply start with x and 15 times multiply it by x. But the same answer can be obtained in just four multiplication, if several times squared to obtain results consistently calculating `x^2`

, `x^4`

, `x^8`

, `x^16`

.

The same idea is generally applicable to any value of n as follows. Write n as a number in the binary system (removing zeros from the left). Then replace each "1" with pair of characters SX, and each "0" with symbol S and delete the leftmost pair of characters "SX". The result is a rule for computing `x^n`

, where "S" is treated as a squaring operation, and "X" as the operation of multiplication by x. For example n = 23 has a binary representation 10111. So we create a sequence SXSSXSXSX, from which we remove the first pair SX to get the final rule SSXSXSX. This rule says that it is necessary to "square, square, multiply by x, square, multiply by x, square and multiply by x", i.e. to calculate consistently the values `x^2`

, `x^4`

, `x^5`

, `x^10`

, `x^11`

, `x^22`

, `x^23`

.

You need to formulate for a given n the corresponding rule for finding `x^n`

.

## Input

One positive integer n, not greater than 2·`10^9`

.

## Output

Print the string for the rule how to raise x to power n to get `x^n`

.