Even indexes (#7842)

Algorithm Analysis

Let's read the input sequence of numbers into an array. Next, using a loop, we will print all the array elements with even indices.

Algorithm Implementation

Declare the working array.

int m[101];

Read the number of input numbers $n$ .

scanf("%d", &n);

Read the input array.

for (i = 0; i < n; i++)
    scanf("%d", &m[i]);

Print the array elements with even indices.

for (i = 0; i < n; i++)
    if (i % 2 == 0)
        printf("%d ", m[i]);

Java Implementation

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        int n = con.nextInt();
        int m[] = new int[n];
        for (int i = 0; i < n; i++)
            m[i] = con.nextInt();
        
        for (int i = 0; i < n; i++)
            if (i % 2 == 0) System.out.print(m[i] + " ");
        
        con.close();
    }
}

Python Implementation

n = int(input())
lst = list(map(int, input().split()))
for i in range(n):
    if i % 2 == 0: print(lst[i], end = " ")