Point

Execution time limit is 1 second

Runtime memory usage limit is 128 megabytes

The point is given with its x and y coordinates: (x, y).

Two points (a, b), (c, d) and an integer n are given. Add them.

Adding two points means to add the corresponding coordinates: (1, 2) + (3, 4) = (4, 6).
Adding point and a number means to add a number to both point coordinates: (1, 2) + 10 = (11, 12).

Write the code according to the next interface:

class Point // C++
{
private:
  int x, y;
public:
  Point(int x = 0, int y = 0); // Constructor
  void Read(void); // Read vector coordinates
  void Print(void); // Print vector coordinates
  Point operator +(int v); // Overload operator +: return the sum of point and integer v
  Point operator +(Point &p); // Overload operator +: return the sum of two points
  int getX(void); // Return x coordinate
  int getY(void); // Return y coordinate
  void SetX(int x); // Set x coordinate
  void SetY(int y); // Set y coordinate
};

class Point // Java
{
  private int x, y;
  Point(int x, int y); // Constructor
  public String toString(); // Return the string with point coordinates
  public Point Add(int v); // Add to both point coordinates the value of v, return the point
  public Point Add(Point p); // Add point p, return the sum of to points
  public int getX(); // Return x coordinate
  public int getY(); // Return y coordinate
  public void SetX(int x); // Set x coordinate
  public void SetY(int y); // Set y coordinate
};

Input

The first line contains the coordinates a and b of the first point. The second line contains the coordinates c and d of the second point. The third line contains an integer n. All values do not exceed 10000 by the absolute value.

Output

Print the sum of two points and a number.

Examples

Input #1

Answer #1

Submissions 1K

Acceptance rate 72%