Editorial

Read the elements of the sequence one by one using a loop and immediately print the odd ones. A number $val$ is considered odd if $val\%2\ne 0$. However, the condition $val\%2==1$ is incorrect for checking the oddness of negative values of $val$. In the C language, dividing a negative odd number by $2$ results in $-1$.

Algorithm implementation — loop

Read the number of input values $n$.

scanf("%d",&n);

Process the $n$ numbers sequentially in a loop.

for(i = 0; i < n; i++)
{
  scanf("%d",&val);

If the number $val$ is odd, print it.

  //if (val % 2 == 1 || val % 2 == -1) printf("%d ",val);
  if (val % 2 != 0) printf("%d ",val);
}

Algorithm implementation — array

Declare an array.

int m[101];

Read the input sequence of integers into the array $m$.

scanf("%d",&n);
for (i = 0; i < n; i++)
  scanf("%d", &m[i]);

Iterate through the numbers in the array. If $m[i]$ is odd, print it.

for (i = 0; i < n; i++)
  if (m[i] % 2 != 0) printf("%d ", m[i]);
printf("\n");

Java implementation

import java.util.*;

class Main 
{
  public static void main(String[] args) 
  {
    Scanner con = new Scanner(System.in);

Read the number of input values $n$.

    int n = con.nextInt();

Read the input sequence of $n$ integers.

    for(int i = 0; i < n; i++)
    {
      int val = con.nextInt();

If the number $val$ is odd, print it.

      if (val % 2 != 0) System.out.print(val + " ");
    }
    System.out.println();
    con.close();
  }
}

Python implementation

Read the input sequence of integers into the list $lst$.

n = int(input())
lst = list(map(int,input().split()))

Process the $n$ numbers in the list $lst$ using a loop.

for x in lst:

If the number $x$ is odd, print it.

  if x % 2 != 0:
    print(x, end = " ")

Python implementation — list

Read the input sequence of integers into the list $lst$.

n = int(input())
lst = list(map(int,input().split()))

Process the $n$ numbers in the list $lst$ using a loop.

for i in range(n):

If the number $lst[i]$ is odd, print it.

  if lst[i] % 2 != 0:
    print(lst[i],end = " ")