Even or Odd (#8371)

Algorithm Analysis

We use a conditional statement to determine the parity of a number.

Algorithm Implementation

Read the input number $n$ .

scanf("%d", &n);

Depending on the parity of $n$ , print the corresponding answer.

if (n % 2 == 0)
    printf("EVEN\n");
else
    printf("ODD\n");

Algorithm Implementation – Ternary Operator

#include <stdio.h>

int n;

int main(void)
{
    scanf("%d", &n);
    (n % 2 == 0) ? puts("EVEN") : puts("ODD");
    return 0;
}

Algorithm Implementation – Switch

#include <stdio.h>

int n;

int main(void)
{
    scanf("%d", &n);
    switch (n % 2 == 0)
    {
        case 1:
            puts("EVEN");
            break;
        case 0:
            puts("ODD");
    }
    return 0;
}

Java Implementation

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        int n = con.nextInt();
        if (n % 2 == 0)
            System.out.println("EVEN");
        else
            System.out.println("ODD");
        con.close();
    }
}

Java Implementation – Ternary Operator

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        int n = con.nextInt();
        System.out.println((n % 2 == 0) ? "EVEN" : "ODD");
        con.close();
    }
}

Java Implementation – Switch

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        int n = con.nextInt();
        switch (n % 2)
        {
            case 0:
                System.out.println("EVEN");
                break;
            case 1:
                System.out.println("ODD");
        }
        con.close();
    }
}