Conditional statement - 2 (#8521)

Algorithm Analysis

To solve the problem, we will use a conditional statement. Since $x \leq 10000 = 1 0^{4}$ , then $x^{3} \leq 1 0^{12}$ . We will use the type long long to avoid overflow.

Algorithm Implementation

Read the input value $x$ .

scanf("%lld",&x);

Calculate the value of $y$ .

if (x >= 10)
    y = x * x * x + 5 * x;
else
    y = x * x - 2 * x + 4;

Output the result.

printf("%lld\n",y);

Algorithm Implementation – Ternary Operator

Read the input value $x$ .

scanf("%lld",&x);

Calculate the value of $y$ .

y = (x >= 10) ? x * x * x + 5 * x : x * x - 2 * x + 4;

Output the result.

printf("%lld\n",y);

Java Implementation

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        long y, x = con.nextLong();
        if (x >= 10)
            y = x * x * x + 5 * x;
        else
            y = x * x - 2 * x + 4;
        System.out.println(y);
        con.close();
    }
}

Python Implementation

Read the input value $x$ .

x = int(input())

Calculate the value of $y$ .

if x >= 10:
    y = x * x * x + 5 * x
else:
    y = x * x - 2 * x + 4

Output the result.

print(y)