Algorithm Analysis

We will use a for loop. We will iterate over all numbers from $a$ to $b$ in ascending order and print the odd ones.

Algorithm Implementation

Read the input data.

scanf("%d %d", &a, &b);

Iterate over numbers from $a$ to $b$ in ascending order and print the odd ones.

for (i = a; i <= b; i++)
    if (i % 2 == 1)
        printf("%d ", i);

Java Implementation

import java.util.*;

class Main {
    public static void main(String[] args) {
        Scanner con = new Scanner(System.in);
        int a = con.nextInt();
        int b = con.nextInt();
        for(int i = a; i <= b; i++)
            if (i % 2 == 1)
                System.out.print(i + " ");
        con.close();
    }
}

Python Implementation

Read the input data.

a, b = map(int, input().split())

Iterate over numbers from $a$ to $b$ in ascending order and print the odd ones.

for i in range(a, b + 1):
    if i % 2 == 1: 
        print(i, end=" ")