Editorial

The problem can be solved using a loop. Read and print each element of the array immediately, one per line.

Alternatively, the problem can be solved using an array. First, read the input sequence into an array. Then, print its elements in the specified order.

Algorithm realization

Read the value of $n$ .

scanf("%d", &n);

Read the elements of the array in a loop and print them one by one, each on a new line.

for (i = 0; i < n; i++)
{
  scanf("%d", &a);
  printf("%d\n", a);
}

Algorithm realization — array

Declare an array to store the sequence.

int m[101];

Read the input data.

scanf("%d", &n);
for (i = 0; i < n; i++)
  scanf("%d", &m[i]);

Print an array of integers, each on a separate line.

for (i = 0; i < n; i++)
  printf("%d\n", m[i]);

Java realization


import java.util.*;

public class Main
{
  public static void main(String[] args)
  {
    Scanner con = new Scanner(System.in);
    int n = con.nextInt();
    int m[] = new int[n];
    for (int i = 0; i < n; i++)
      m[i] = con.nextInt();

    for (int i = 0; i < n; i++)
      System.out.println(m[i]);
    con.close();
  }
}

Python realization

Read the input data.

n = int(input())
lst = list(map(int,input().split()))

Print a list $l s t$ of integers, each on a separate line.

for i in range(n):
  print(lst[i])

Python realization — list

Read the input data.

n = int(input())
lst = list(map(int,input().split()))

Print a list $l s t$ of integers, each on a separate line.

for x in lst:
  print(x)