Delete a letter (#8985)

Algorithm Analysis

Declare two pointers at the beginning of the array: i = j = 0. Move the pointer i through the characters of the string. For each character of the string s, not equal to ‘a’, we copy s[i] to s[j] and move the pointer j one position forward.

Algorithm Implementation

Declare a character array.

char s[1001];

Read the input string.

fgets(s, sizeof(s), stdin);

Move letters, different from ‘a’, to the left.

int j = 0;
for (int i = 0; i < strlen(s); i++)
    if (s[i] != 'a') s[j++] = s[i];

At the end of the resulting string, put a null byte.

s[j] = 0;

Output the result.

puts(s);

Algorithm Implementation – C++

Read the input string.

getline(cin, s);

Attach letters, different from ‘a’, to the resulting string res.

for (int i = 0; i < s.length(); i++)
    if (s[i] != 'a') res = res + s[i];

Output the result.

cout << res;

Java Implementation

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        String s = con.nextLine();
        String res = "";
        for(int i = 0; i < s.length(); i++)
            if (s.charAt(i) != 'a') res = res + s.charAt(i);
        System.out.printf(res);
        con.close();
    }
}

Java Implementation – replace

import java.util.*;

public class Main
{
    public static void main(String[] args)
    {
        Scanner con = new Scanner(System.in);
        String s = con.nextLine();
        s = s.replace("a", "");
        System.out.printf(s);
        con.close();
    }
}

Python Implementation

s = input()
print(s.replace('a', ''))