Algorithm Analysis

Let $n$ be a three-digit number. Then:

the number of hundreds $a$ equals $n /100$ ;
the number of tens $b$ equals $n /10%10$ ;
the number of units $c$ equals $n %10$ .

It remains to calculate and print the product $a \cdot b \cdot c$ .

Algorithm Implementation

Read the input data.

scanf("%d", &n);

Calculate the digit of hundreds $a$ , tens $b$ , and units $c$ .

a = n / 100;
b = n / 10 % 10;
c = n % 10;

Calculate and print the product of the digits of the number.

res = a * b * c;
printf("%d\n", res);

Java Implementation

import java.util.*;

public class Main
{
    public static void main(String []args)
    {
        Scanner con = new Scanner(System.in);
        int n = con.nextInt();
        int a = n / 100;
        int b = n / 10 % 10;
        int c = n % 10;
        int res = a * b * c;
        System.out.println(res);
        con.close();
    }
}

Python Implementation

n = int(input())
a = n // 100
b = n // 10 % 10
c = n % 10
res = a * b * c
print(res)