Editorial

For each type of toy, read its quantity and price. If the price is less than $50$ grn, add the number of such toys to the total count.

Algorithm realization

Read the number of toy types $n$ .

scanf("%d",&n);

Use the variable $res$ to store the total count of toys with a price less than $50$ grn.

res = 0;

Read and process the information about toys.

for(i = 0; i < n; i++)
{
  scanf("%d %lf",&num,&price);
  if (price < 50.0) res += num;
}

Print the answer.

printf("%d\n",res);

Java realization

import java.util.*;

public class Main
{
  public static void main(String[] args)
  {
    Scanner con = new Scanner(System.in);
    //con.useLocale(new Locale("US"));
    //con.useLocale(Locale.US);
    int res = 0;
    int n = con.nextInt();
    for (int i = 0; i < n; i++)
    {
      int num = con.nextInt();        
      double price = con.nextDouble();
      if (price < 50.0) res += num;
    }
    System.out.println(res);
    con.close();
  }
}

Python realization

Read the number of toy types $n$ .

n = int(input())

Use the variable $res$ to store the total count of toys with a price less than $50$ grn.

res = 0

Read and process the information about toys.

for _ in range(n):
  num, price = input().split()
  num = int(num)
  price = float(price)
  if price < 50.0: res += num

Print the answer.

print(res)